iJoseph Posted August 14, 2010 Share Posted August 14, 2010 I have the following code, (I'm sorry it's so long an it does more that the question asks.) It's ment to edit, delete and make new links in a mysql database, by also using a link header to home all the links (Like a dropdown menu) And thig manages the links. However then the update, or when the new form is submitted it leaves then titlereg field blank. (The titlereg is the id of the main link, it's called reg in the title_reg database) I know this is complicated and i'm not too good at explaining the problem but any help would be great. I have commented on anything that could help. <?php include "../includes/mysql_connect.php"; include "../includes/info_files.php"; echo "<strong>Links</strong><br />"; echo "Currect links:<br /><br />"; if($_POST['submit']){ $name = mysql_real_escape_string($_POST['name']); $titlereg = mysql_real_escape_string($_POST['titlereg']); $url = mysql_real_escape_string($_POST['url']); $id = mysql_real_escape_string($_POST['id']); mysql_query("UPDATE nav_sub SET name='$name', SET titlereg='$titlereg', SET url='$url' WHERE reg='$id'"); ////////////////////////////////// Here will help, the update MY SQL thingie echo "Link Changed.<br /><br />"; } elseif($_POST['remove']){ $id = mysql_real_escape_string($_POST['id']); mysql_query("DELETE FROM nav_sub WHERE reg='$id'"); echo "Link deleted.<br /><br />"; } else{ $result = mysql_query("SELECT * FROM nav_sub"); while($row = mysql_fetch_array($result)) { echo '<strong>' . $row['name'] . '</strong>'; echo '<form action="" method="post">'; echo 'Name: <input type="text" name="name" value="' . $row['name'] . '" /><br />'; echo 'Link: <input type="text" name="text" value="' . $row['url'] . '" /><br />'; echo 'Navigation title: <select name="titlereg">'; $resultabc = mysql_query("SELECT * FROM nav_title"); while($rowabc = mysql_fetch_array($resultabc)) { echo '<option value="' . $rowabc['reg'] . '">' . $rowabc['name'] . '</option>'; ////////////////////////////////// Here is the option } echo '</select>'; echo '<input type="hidden" name="id" value="' . $row['reg'] . '" />'; echo '<input type="submit" name="submit" value="Change" /> <input type="submit" name="remove" value="Remove" /><br />'; echo '</form>'; } } echo "New link:<br /><br />"; if($_POST['new_submit']){ ////////////////////////////////// Here!!!!!!!!!!!!!!! $result = mysql_query("SELECT * FROM nav_sub"); $new_titlereg = $_POST['new_titlereg']; $new_name = mysql_real_escape_string($_POST['new_name']); $new_url = mysql_real_escape_string($_POST['new_url']); mysql_query("INSERT INTO `nav_sub` (`titlereg` ,`reg` ,`name` ,`url`)VALUES ('$new_titlereg', '', '$new_name', '$new_url')"); ////////////////////////////////// here is the MY SQL statement... echo "Link added.<br /><br />"; } echo '<form action="" method="post">'; echo 'Name: <input type="text" name="new_name" value="" /><br />'; echo 'Url: <input type="text" name="new_url" value="" /> \\\\ If your linking to a page you made, then the url is index.php?catt=(The categrory you put)&page=(The page you put)<br />'; echo 'Navigation title: <select name="new_titlereg">'; $resultab = mysql_query("SELECT * FROM nav_title"); while($rowab = mysql_fetch_array($resultab)) { echo '<option value="' . $rowab['reg'] . '">' . $rowab['name'] . '</option>'; ////////////////////////////////// Here isn't submitting the value in the option } echo '</select>'; echo '<input type="submit" name="new_submit" value="Insert" /><br />'; echo '</form>'; ?> By the way, explain simply as I'm only 13 Quote Link to comment https://forums.phpfreaks.com/topic/210720-php-help-updating-a-mysql-database-with-forms/ Share on other sites More sharing options...
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